Question

the velocity time graph for a body moving with constant velocity is shown in figure below. Calculate the magnitude of displacement during the time interval from the graph.
(a) t1 = 5sec to t2 = 9sec
(b) t1 = 0sec to t2 = 10sec​

Answer 1

Answer:

a. time=9-5=4 seconds

v=5 m/s

DISPLACEMENT =5×4=20 m

b. time=10-0=10 seconds

v=5 m/s

DISPLACEMENT =5×10=50 m.

Answer 2

Answer:

Finally we will look at a few example computations of the area for a few trapezoids. The solution for finding the area is shown for the first example below. The shaded trapezoid on the velocity-time graph has a base of 2 seconds and heights of 10 m/s (on the left side) and 30 m/s (on the right side). Since the area of trapezoid is found by using the formula A = ½ * (b) * (h1 + h2), the area is 40 m [½ * (2 s) * (10 m/s + 30 m/s)]. That is, the object was displaced 40 meters during the time interval from 1 second to 3 seconds.

Explanation: