The Velocity Time Graph for a moving object is shown in the figure. Total displacement of the object during the time interval when there is non zero acceleration and retardation is;
1. 60 m
2. 50 m
3. 30 m
4. 40 m
Answers
here we know that
vxt = displacemet when we find the area of those two equilatoral trapizum under the curve then its give us the displacement
displacement = 25 + 25
displacement = 50m
The correct answer is option (2) 50 m.
Given,
The velocity-time graph for a moving particle.
To Find,
The total displacement of the object during the time interval when there is non-zero acceleration and retardation.
Solution,
The total displacement of the object during the time interval when there is non-zero acceleration and retardation will be equal to the area under the graph between the time interval 20 to 40.
Now,
Displacement = Area of the rectangle with base 20 and height 1 + Area of the triangle with height 3 and base 20.
Displacement = 20(1)+1/2(3)(20)
Displacement = 20+30 = 50 m
Hence, the displacement of the object during non-zero acceleration and retardation is 50 m.
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