The velocity-time graph for a particle is shown in the figure ,then?
16. The distance and displacement of the particle from 0 to 15 seconds is
(1) 100 m, 50 m
(2) 100 m, 100 m
(3) 100 m, 200 m
(4) 100 m, 0m
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The distance will be equal to displacement as the graph is not in the negative direction.
Displacement = Area under the graph
= 1/2bh + lb
= 1/2 x 10 x 15 + 5 x 5
= 75 + 25
= 100 m
Hope it helps
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