Question

The velocity−time graph for the motion of a car is shown in the given figure.
(a) What is the total distance travelled by the car?
(b) What is the speed of the car (in km/h) at 8th second?
(c) What is the acceleration of the car
(i) during the first 6 s?
(ii) during the last 2 s?
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Answer 1

Answer:

I know it is hard to understand but you understand something

Explanation:

See this picture

Answer 2

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To Find

(a) What is the total distance travelled by the car?

(b) What is the speed of the car (in km/h) at 8th second?

(c) What is the acceleration of the car

(i) During the first 6 s

(ii) During the last 2 s

Solution

Calculating acceleration of car from 0-6 s,

➝ v = u + at

➝ 15 = 5 + 6a

➝ 15 - 5 = 6a

➝ 6a = 10

➝ a = 10/6

After cancelling, we get :-

➝ a = 1.67 m/s²

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◈ (a)

Calculating distance travelled in 0-6 s,

➳ s = ut + 1/2 at²

➳ s = 5 × 6 + 1/2 × 1.67 × 36

➳ s = 30 + 30

➳ s = 60 m

Calculating distance travelled in 6-10 s,

➪ Distance = Speed × Time

➪ Distance = 15 × 4

➪ Distance = 60 m

So, total distance :-

⪼ 60 + 60

⪼ 120 m

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◈ (b)

At 8th s, car us moving with velocity 15 m/s

So,

→ Speed in km/h = 15 × 18/5

→ Speed in km/h = 54 km/h

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◈ (c)

Acceleration of car during 1st 6s is calculated above, i.e, 1.67 m/s²

During last 2 s, car us moving with constant velocity of 15 m/s. So, it's acceleration is 0 m/s²

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