Question

the velocity time graph for the vertical component of the velocity of a body thrown upward from the ground and landing on the roof of a building is given in the figure .the height of the building?​

Answer 1

$\bold {\huge {Your ~answer :-}}$

$\bf\huge\boxed{40\:m}$

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We know that,

Height = area under v-t graph

So, height(h)

$h = \frac{1}{2} \times 30 \times 3 - \frac{1}{2} \times 10 \times 1$

$h = \frac{1}{2} \times 90 - \frac{1}{2} \times 10$

h = 45 - 5

h = 40

Hence the Height of the Building = 40 m

$\huge{\red{\ddot{\smile}}}$

Answer 2

Explanation:

We know that,

Height = area under v-t graph

So, height(h)

h = \frac{1}{2} \times 30 \times 3 - \frac{1}{2} \times 10 \times 1h=

2

1

×30×3−

2

1

×10×1

h = \frac{1}{2} \times 90 - \frac{1}{2} \times 10h=

2

1

×90−

2

1

×10

h = 45 - 5

h = 40

Hence the Height of the Building = 40 m