Question

The velocity-time graph of a ball of mass 200 g moving along the straight line under the action of 10 N

force is given below. Find the friction force exerted by the floor on the ball.​

Answer 1

Mass of the body, m=20 g=0.02 kg

Mass of the body, m=20 g=0.02 kgFrom the given graph, we note that

Mass of the body, m=20 g=0.02 kgFrom the given graph, we note thatInitial velocity, u=20 m/s=20 m/s

Mass of the body, m=20 g=0.02 kgFrom the given graph, we note thatInitial velocity, u=20 m/s=20 m/sFinal velocity, v=0 m/s

Mass of the body, m=20 g=0.02 kgFrom the given graph, we note thatInitial velocity, u=20 m/s=20 m/sFinal velocity, v=0 m/sTime taken, t=10−0=10s

Mass of the body, m=20 g=0.02 kgFrom the given graph, we note thatInitial velocity, u=20 m/s=20 m/sFinal velocity, v=0 m/sTime taken, t=10−0=10sThe force exerted on the ball is,

Mass of the body, m=20 g=0.02 kgFrom the given graph, we note thatInitial velocity, u=20 m/s=20 m/sFinal velocity, v=0 m/sTime taken, t=10−0=10sThe force exerted on the ball is,F=m x a

Mass of the body, m=20 g=0.02 kgFrom the given graph, we note thatInitial velocity, u=20 m/s=20 m/sFinal velocity, v=0 m/sTime taken, t=10−0=10sThe force exerted on the ball is,F=m x aF=m x (v−u)/t

Mass of the body, m=20 g=0.02 kgFrom the given graph, we note thatInitial velocity, u=20 m/s=20 m/sFinal velocity, v=0 m/sTime taken, t=10−0=10sThe force exerted on the ball is,F=m x aF=m x (v−u)/tF=−0.04 N

Mass of the body, m=20 g=0.02 kgFrom the given graph, we note thatInitial velocity, u=20 m/s=20 m/sFinal velocity, v=0 m/sTime taken, t=10−0=10sThe force exerted on the ball is,F=m x aF=m x (v−u)/tF=−0.04 NThe negative sign shows that the friction force exerted by the table is opposite to the direction of motion of the ball.

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