The velocity time graph of a ball of mass 20g moving along a straight line on a long table is given below. How much force does the table exert on the ball to bring it to rest.
Answers
The given question is incomplete please refer to the graph shown below:
The velocity-time graph of a ball of mass 20g moving along a straight line on a long table is given below. How much force does the table exert on the ball to bring it to rest.
Concept:
We need to utilize the definition of force having the formula, F = ma where a = v - u/ t
Given:
Mass of ball= 20g
From the graph,
initial velocity, u = 20 m/s
Final velocity, v = 0m/s
Find:
We need to determine the force exerted by the table on the ball to bring it to rest.
Solution:
- A force is an influence that can alter an object's motion, according to physics.
- An obvious way to describe force is as a push or a pull.
- The fact that a force has both a magnitude and a direction makes it a vector quantity.
- Mathematically, Force can be expressed as by the formula- F = ma where m represents mass and a represents acceleration
From the graph we have,
initial velocity as 20 m/s and final velocity as 0m/s
The time taken, t = 10 -0 = 10secs
We know, a = (v - u)/t where v = final velocity, u = initial velocity and t = time
Therefore, euation for force becomes-
F = ma
F = m×(v-u)/t
F = 20×(0-20)/10
F = -0.04 N
The negative sign indicates that the table's friction force acts against the ball's motion in the opposite direction.
Thus, the force exerted by the table on the ball to bring it to rest is -0.04 N
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Answer:
Explanation:
The acceleration a is --0.02m