The velocity-time graph of a ball of mass 30 g moving along a straight line is given in the figure. The force that brings the ball to rest will be:
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Answer:
0.03 N
Explanation:
as given in the question
final velocity v = 0
at t=0 , initial velocity u = 5 m/s ( we can see in the graph )
time t = 5 sec
now acceleration a = v-u/ t
a = 0 - 5 / 5
a = -1 m/s^2
put this value of a in F = ma
F = (30/1000) * ( - 1)
= (- 0.03) N
here the sign of - means that the force is applied on the opposite direction to the motion
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