Question

The velocity-time graph of a body is shown in fig.
(a) State the kind of motion represented by OA and AB.
(b) What is the velocity of the body at 10 s and at 40 s?
(c) Calculate the distance covered by the body between 10th second and 30th second.​

Answer 1

where is the fig. bro...........????????

Answer 2

Answer:

1) OA represents uniform acceleration since the slope of OA in the velocity-time graph is having a uniform positive slope. AB represents the uniform velocity of 20ms  

−1

. Since the slope of AB is zero. hence, acceleration is zero.

(2) After 10 s, the velocity is 20ms  

−1

 up to 30 s and after 30 s, the velocity is uniformly restarted to zero after 40 s.

(3) Retardation is uniform and it is equal to the slope of BC, i.e.

Slope of BC =  

DC

BD

​

=  

40−30

20

​

=2ms  

−2

 

And acceleration =−2ms  

−2

 

(4) Distance covered by the body between the 10th and 30th second

=20×20=400metres

Explanation: