The velocity - time graph of a body is shown in fig The ratio of the…during the intervals OA and OB is…
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Answer:
From t=0 to t=A velocity increases from 0 to v where v is the velocity at t=A
From t=A to t=B velocity increases from v to 0 where v is the velocity at t=A
Hence, v
avg
during interval 0 to A is same as v
avg
during interval A to B
A−0
v
c
−0
=tan60
∘
=
3
;
∴v
c
=
3
×OA
A−0
v
c
−0
=tan150
∘
=−tan30
∘
=−
3
1
∴v
c
=
3
1
×AB
Equating both v
c
,
3
×OA=
3
1
×AB
⇒
OA
AB
=3
⇒
OA+AB
OA
=
1+3
1
⇒
OB
OA
=
4
1
Distance covered on in time OA: d
OA
=
2
1
×OA×v
A
Distance covered on in time AB: d
AB
=
2
1
×AB×v
A
∣a
OA
∣=tan60
∘
=
3
∣a
AB
∣=tan30
∘
3
1
∣a
AB
∣
∣a
OA
∣
=3
∴
d
AB
d
OA
=
2
1
×AB×v
A
2
1
×OA×v
A
∴
d
AB
d
OA
=
cot30
∘
AC
cot60
∘
AC
=tan60
∘
×cot30
∘
=3
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