The velocity – time graph of a body moving along a straight line is shown below. The acceleration of the body along OA, AB and BC is
Answers
Answer:
the current prime rib cage with the right direction for the people who are not in the world is one of our lives my entire life are mu kn karibi mora kn dekhibaku tk jibini sym mu kn karibi mu bhi
Answer:
. Area of graph above time axis
A=
2
1
×(8−4)×10=60m
Area of graph below time axis
B=
2
1
×4×10=20m
Average velocity in whole time of motion
v
=
Totaltime
Displacement
=
Totaltime
AreaA−AreaB
=
12
60−20
=3.33ms
−1
b. Average speed in whole time of motion
v
av
=
Totaltime
Totaldistance
=
Totaltime
AreaA+AreaB
=
12
60+20
=6.67ms
−1
c. Acceleration:
From 0 to 2 s;
a=
t
2
−t
1
v
2
−v
1
=
2−0
10−0
=5ms
−2
From 2 to 6 s :
a=
t
2
−t
1
v
2
−v
1
=
6−2
10−10
=0
From 10 to 12 s: a=
t
2
−t
1
v
2
−v
1
=
10−6
−10−10
=−5ms
−2
From 10 to 12 s:
a=
t
2
−t
1
v
2
−v
1
=
12−10
0−(−10)
=5ms
−2
Acceleration vs time graph is drawn in figure.
solution
Expand-image