Question

The velocity-time graph of a car is given below . Study the graph and answer the following questions (i) What is the distance travelled by the car in the first 3 seconds? (ii)State the kind of motion represented by OA and AB (iii)What is the velocity of the body after 8 s and after 3 s ?

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Answer 1

Answer:

Explanation:

how can i help you i am asking because there is no time graph

Answer 2

(i) The distance travelled by the car is first 3 seconds is 2.25 m

(ii) OA and AB represents motion with constant acceleration and zero acceleration (constant velocity) respectively

(iii) Velocity after 8 s is 0 and after 3 s is 15 m/s

Explanation:

(i) We know that in a velocity-time graph, the distance travelled in time t = area under the velocity-time graph upto time t

Therefore, distance travelled in the first 3 seconds

= Area of the first right angled triangle

$=\frac{1}{2}\times 3\times 15$

$=22.5$ m

(ii) From graph it is clear that the car moves with a constant acceleration from O to A and then with a constant velocity (zero acceleration) from A to B

(iii) Velocity of the body after 3 seconds = 15 m/s (velocity corresponding to point A on graph)

Velocity of the body after 8 seconds is zero (velocity corresponding to point C on graph)

Hope this answer is helpful.

Know More:

Q: In the given graph, find the velocity of particle at  t=6 s. (Initial velocity = 5 m/s)  a(m/s)

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