Physics, asked by yatinchhetri123, 1 year ago


The velocity time graph of a car is given below. The car weighs 1000kg.
(m/sec)
T (sec)
(i) What is the distance travelled by the car in first 2 sec?
(ii) What is the retarding force at the end of 5 sec to bring the car to stop?
(i) Explain why:-​

Answers

Answered by owaiskhan23
1

Answer:

the distance travelled =area under the graph

distance in first two second = area of triangle Abe

distance=1/2× 2 × 15

15 m

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