The velocity time graph of a car is given below. The car weighs 1000kg.
(m/sec)
T (sec)
(i) What is the distance travelled by the car in first 2 sec?
(ii) What is the retarding force at the end of 5 sec to bring the car to stop?
(i) Explain why:-
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Answer:
the distance travelled =area under the graph
distance in first two second = area of triangle Abe
distance=1/2× 2 × 15
15 m
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