Question

the velocity time graph of a moving body (i) the acceleration in AB, BC and CD. (ii)displacement in each part AB, BC CD (iii)total displacement​

Answer 1

$\qquad\quad\mathcal{\underline{\underline{ANSWER}}}$

The slope of a velocity time graph gives acceleration

(i) Acceleration in AB

⇒ $\sf \dfrac{final \: velocity - initial \: velocity}{2} = \dfrac{30 - 0}{4}$

⇒17.5 m/s

Acceleration in BC = 0 (since the body is at rest)

Acceleration in CD

⇒ $\sf \dfrac{final \: velocity - initial \: velocity}{2} = \dfrac{0-30}{2}$

⇒-15 m/s

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The area enclosed above time axis in a velocity time graph represents the displacement

(ii) Displacement in part AB

⇒ Area of ∆AB4

⇒ 1/2 × 30 × 4

⇒60m

Displacement in part BC

⇒ Area of rectangle 4BC8

⇒ 30 × 4

⇒ 120m

Displacement in part CD

⇒ Area of ∆8CD

⇒ 1/2 × 30 × 2

⇒ 30m

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(iii) Total Displacement

⇒ Displacement of parts AB + BC + CD

⇒ 60 + 120 + 30

⇒ 210m

Answer 2

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