Question

The velocity time graph of a moving train is depicted in figure. The average velocity in first 10 s. is​

Answer 1

Tip: Area under graph = magnitude of displacement.

Answer: 30 m/s (A)

Explanation:

Average velocity = (Total displacement)/(Total time)

=> v = ar(∆AOD)/10s

=> v = 1/2 × 10 × 60 m × 1/10s

=> v = 1/2 × 60 m/s

=> v = 30 m/s.