Question

The velocity-time graph of a particle moving along a straight line is shown in the figure given

The displacement of the particle in 5 second is

1) 0.5 m
2) 1 m
3) 2 m
4) 4 m

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Answer 1

displacement = area of triangle AOB+ Area of triangle BCD + area of rectangle DEFG

=1/2×3×2+1/2×1×-2+2×1

=3-1+2

=4m