The velocity-time graph of a particle moving along a straight line is shown in
Calculate the distance covered by the particle between
(
10 tot 18 seconds.
(ii) t 2 sec, tot = 12 sec. and the maximum value of acceleration during this interval.
v(m/s)
10
6
D
12 14 16 18
Time
Answers
Answered by
0
Step-by-step explanation:
t
v
0
=
25−t−t
1
v
0
=5...(1)
t=25−t−t
1
2t=25−t
1
t
1
=25−2t
s
1
=
2
1
v
0
t
s
2
=v
0
t
1
=v
0
(25−2t)
s
3
=
2
1
×t×v
0
25
(
2
v
0
t
)×2+v
0
(25−2t)
=20
25
v
0
t+25v
0
−2v
0
t
=20
25
25v
0
−v
0
t
=20
v
0
=5t
25×5t−5t
2
=25×20
t
2
−25t+100=0
t
2
−20t−5t+100=0
t(t−20)−5(t−20)=0
t=5s or t=20s
t=5s
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