the velocity time graph of a particle moving along a straight line is given in the adjoining diagrams. Answer the following questions.
*Calculate the distance travelled by the particle in 4sec.
*find the velocity of motion at instant t=5sec.
*at what instant the velocity of the particle is 15ms^-1.
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distance travelled = area under v-t curve
at 4s distance= 4×20= 80m
in this case the acceleration of the particle = slope= 5/1= 5m/s^2
Now velocity at 5s = u+at = 0+5×5 =25m/s
from the graph we can see that at 3 s the velocity of the particle is 15m/s
Hope it helps.
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at 4s distance= 4×20= 80m
in this case the acceleration of the particle = slope= 5/1= 5m/s^2
Now velocity at 5s = u+at = 0+5×5 =25m/s
from the graph we can see that at 3 s the velocity of the particle is 15m/s
Hope it helps.
✌
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