Question

The velocity-time graph of a particle moving in a straight line is shown in the figure below. Find the distance travelled by particle in the first 4 sec. A B 20+ 1 wor с D Velocity (m/s) 10 1 1 la to 2 Time (sec) 3​

Answer 1

Answer:

d = 55 m

Explanation:

area of the graph = vt = distance

distance= area of triangle aoA + area of rectangle aABba + area of triangle ecBe + area of square ebcCe + area of square cdDCc

distance = 1/2*1*20 + 1*20 + 1/2*1*10 + 1*10 + 1 * 10

distance = 10+ 20 + 5 + 10 + 10

distance= 55 m

Answer 2

Answer:

Explanation:

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