Question

The velocity-time graph of a train is shown below. From the graph, find (i) the acceleration of the train during the time interval (a) 0 to 3s (b) 3 to 53s (c) 53 to 57s (ii) the displacement of the train in the first 53s.

Answer 1

Answer:

(i) Acceleration = (30-0)/3 = 10 m s^-2

(ii) Acceleration = There is no acceleration from 3s to 53s as the train moves with constant velocity.

(iii) Acceleration = (0-30)/(57-53) = -30 /4 = -7.5 m s^-2(As the sign is negative therefore it is retardation. Retardation = 7.5 m s^-2)

Hope it helps you.

Explanation:

Answer 2

Answer:

slope of the velocity-time graph gives acceleration and area under the velocity time graph gives displacement.