Question

The velocity-time graph of an object moving along a straight line is as shown. Calculate distance covered by object between t = 0 s to t =10 s.

O 140 m
0 130 m
O 100 m
O 125 ​

Answer 1

Answer:

option (b) 130 m

Explanation:

in the given graph distance covered in time t0 to t2

= area of 1 triangle = 1/2 *20*2 = 20 m

distance covered in time t2 to t5

= area of 2 rectangle = 20*3 = 60 m

distance covered in time t5 to t10

= area of 3 triangle = 1/2 * 5*20 = 50 m

total distance covered = 20 + 50 + 60 = 130 m