Question

the velocity time graph of an object moving along straight line is shown in figure calculate :-. (1) distance between t=0 to t= 5second . (2) distance between t=0 to. t= 10seconds

Answer 1

+++++++++++++++++++++++++++++{
we know that
velocity × time = distance

=====. in velocity time graph area covered by velocity time gives the distance
hence
area covered I triangle 1st I.e. t=0 to t= 2sec
so distance covered

= 2 ×20 /2
20m

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2) 20× 2/2 +3×20 + 5× 20/2

= 20 +60 +50
=130m

(area of first triangle + area of rectangle +area of triangle)
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