Question

the velocity time graph of an object of mass 50 gram if shown in figure. study the graph and answer the following questions
(i)calculate the force acting on the object in the time interval 0-3s.
ii)calculate the force acting on the object in the time interval 6-10s.
iii) is there any time interval in which no force acts on the object ? justify your answer.​

Answer 1

Answer:

Here is your answer

Explanation:

If Mass of the Object = 0.05 kg

Initial Velocity = 0 m/s

Final Velocity = 120 m/s

Accelaration = 40 m/s^2

Force = Mass x Accelaartion

Force = 0.05 kg x 40 m/s^2

2 Newton = Force

So the Force acting is 2 Newtons

Mass of the Object = 0.05 kg

Initial Velocity = 120 m/s

Final Velocity = 0 m/s

Accelaration = - 30 m/s^2 (Retardation)

Force = Mass x Accelaration

Force = 0.05 kg x ( - 30 m/s^2)

Force = -1.5 Newton

So, the force of -1.5 Newton acts on it

Time Interval of 3 to 6 Seconds no Force acts on the body because both are at the constant speed between those time intervals.

Answer 2

Explanation:

acceleration= v-u/t

a= 120-0/3= 40m/s

m= 50/1000 ( convert into g to kg)

m=1/2

F×ma= 1/20×40=2N

2. 0×120/10-6 = -120/4= -30 m/s²

1/20 × (-30)= -1.5N

3. velocity of the object is constant and so the acceleration is 0.

HOPE ITS HELPFUL..