Physics, asked by rujulac14, 3 months ago

The velocity time graph of runner is given in the graph.
(a) What is the total distance covered by the runner in 16 s?
(b) What is the acceleration of the runner at time t = 11 s?

Attachments:

Answers

Answered by b22554113
19

Answer:

Mark me as Brainlist please

The total distance is 130 m and the acceleration is zero at 11 second.

Explanation:

(a). The total distance covered in 16 seconds.

The total distance = Area of triangle +area of rectangular

D=1/2*h*b+w*l

D=1/2*10*6+10*10

D=130m.

(b). The acceleration of the runner at t = 11 seconds.

The velocity is not changing at 11 second so the acceleration will be zero.

Hence, The total distance is 130 m and the acceleration is zero at 11 second.

Mark me as Brainlist please

Answered by preetikanadar05
5

Answer:

Answer : (a) The total distance covered by the runner in 16s is 10m/s

Answer : (b) The acceleration of the runner at time t=11s is 10/11m/s

Explanation:

(b) acceleration= velocity/time

therefore 10/11m/s

HOPE IT HELP YOU

Similar questions