Question

The velocity time graph of the motion of a particle moving in a straight line is given in the adjoining diagram. Draw the below diagram shown, read the graph to answer the following questions: (Lesson -2) (i) Calculate the distance travelled by the particle in 4s. (1) (ii) Find the velocity of motion at instant t = 5s. (½) (iii) At what instant the velocity of the particle is 15m s–

Answer 1

distance travelled = area under v-t curve
at 4s distance= 4×20= 80m

in this case the acceleration of the particle = slope= 5/1= 5m/s^2
Now velocity at 5s = u+at = 0+5×5 =25m/s

from the graph we can see that at 3 s the velocity of the particle is 15m/s

Hope it helps.

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Answer 2

Answer:

distance travelled = area under v-t curve

at 4s distance= 4×20= 80m

in this case the acceleration of the particle = slope= 5/1= 5m/s^2

Now velocity at 5s = u+at = 0+5×5 =25m/s

from the graph we can see that at 3 s the velocity of the particle is 15m/s