the velocity time graph particle moving in a straight line is a straight line is shown in figure.
the acceleration of the particle at 9 second and find acceleration
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khyat:
fast looking ans do
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Answered by
6
option 3 is correct
by looking at the graph you can predict the velocity is decreasing from 15 to 10 so it is deacceleration which is equal to (15-10)/(10-8)
= -5/2 m/s2
by looking at the graph you can predict the velocity is decreasing from 15 to 10 so it is deacceleration which is equal to (15-10)/(10-8)
= -5/2 m/s2
do you know how to calculate sope of a straight line
slope
no
y= mx +c
yes or no
ans my another question
yes where m is the slope now use the formula to calculate the slope that is (y2y1)/(x2x1)
(y2-y1)/(x2-x1)
where (x1, y1) = (15, 8) and (x2, y2) = (10, 10)
sorry (x1, y1) = (8, 15)
Answered by
1
Explanation:
option 3 is obsolete correct.
-5/2 ms-²
please give me brainlist and
Follow vote and thanks.
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