Question

The velocity-time graph shows the motion of a cyclist. Find

(i) its acceleration

(ii) its velocity and

iii) the distance covered by the cyclist in 15 seconds.​

Answer 1

Answer:

Correct option is

A

300

(a)Since velocity is not changing, acceleration is equal to zero.

(b) Reading the graph, velocity=20ms

−1

(c) s = area of the figure enclosed under v-t graph. Distance covered in 15s, s=ut=20×15=300m

Answer 2

Answer:

Explanation:

• In a velocity time graph, the slope of graph tell us about the acceleration. If the slope is high then the acceleration is positive, if the solve is low then the acceleration is negative and if the slope is parallel to time axis then there is no acceleration taking place!

•️ In the velocity time graph the distance or displacement can be founded by the area under the curve!

Required solution:

The velocity-time graph shows the motion of a cyclist. Find

Question 1. Its acceleration!?

Answer 1.

Here, final velocity (v) is 20 m/s, initial velocity (u) is 20 m/s and time (t) is 25 seconds {Because 25 - 0 = 25}

$:\implies \sf Acceleration \: = \dfrac{Change \: in \: velocity}{Time} \\ \\ :\implies \sf a \: = \dfrac{v-u}{t} \\ \\ :\implies \sf a \: = \dfrac{20-20}{25} \\ \\ :\implies \sf a \: = \dfrac{0}{25} \\ \\ :\implies \sf a \: = 0 \: ms^{-2} \\ \\ :\implies \sf Acceleration \: = 0 \: ms^{-2}$

Explanation: Here, acceleration is zero because we are able to see that the slope of the graph is parallel to the time axis therefore, the acceleration is zero, when velocity is constant then the acceleration must be zero!

Question 2. Its velocity!?

Answer 2.

We are able to see that the slope of the graph shows that the velocity is 20 metre per second.

Question 3. The distance covered by the cyclist in 15 seconds!?

Answer 3.

$:\implies \sf s \: = Area \: under \: curve \\ \\ :\implies \sf Distance \: = Area \: under \: curve \\ \\ :\implies \sf Distance \: = Area \: of \: rectangle \\ \\ :\implies \sf Distance \: = Length \times Breadth \\ \\ :\implies \sf Distance \: = (15-0) \times (20-0) \\ \\ :\implies \sf Distance \: = 15 \times 20 \\ \\ :\implies \sf Distance \: = 300 \: m$