Physics, asked by astroallie06, 8 months ago

The velocity-time graphs of a car and a scooter are shown in the figure. The difference between the distance travelled by the car and the scooter in 15 s and (i) the time at which the car will catch up with the scooter are, respectively?​

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Answered by vtraders8
10

distance travel by scooter School 30 x 15 is = to 450 metre distance travel by car 1 by 2 multiply 15 x 45 is = I 337.5 metre the difference between the distance by scooter and the car in 15 second = 112.5 metre total at t = t1 car catch up with scooter 30t = 330 7.5 + 45 + (- 15) t= 22.5 second

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