Question

.
The velocity-time relation of a body starting from
rest is given by v = k^2t^3/2, where K = √2(m^1/2)/(s^5/4)
The distance traversed in 4 seconds is
(1) 2.00 m
(2) 2.56 m
(3) 25.6 m
(4) 256 m​

Answer 1

Explanation:

Answer is 25.6m

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