The velocity-time relation of an electron starting
from rest is given by u.-ktwhere k=2m/s.
The distance traversed in 3 sec is :-
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The correct question is:
The velocity time relation of an electron starting from rest is given by u=kt where k = 2 m/s². What is the distance traversed in 3 seconds?
We know that Distance = Speed × Time
According to the relation given,
- u = kt
- k = 2m/s²
⇒ u = 2 × t = 2t m/s
It is given that we have to identify the distance travelled in 3 seconds.
⇒ t = 3
⇒ u = 2 × 3 = 6 m/s
Now we know the speed and the time. Hence substituting in the distance formula we get,
⇒ Distance = Speed × Time
⇒ Distance = 6 m/s × 3 sec
⇒ Distance = 18 m
Hence the distance traversed in 3 seconds is 18 m.
Hope it helped !!
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