Question

The velocity-time relation of an electron starting

from rest is given by v = kt, where

2

k 2 m/s .

The distance traversed in 3 sec is:

(a) 9 m (b) 16 m

(c) 27 m (d) 36 m​

Answer 1

Given::-

u = 0

v = kt

k = 3m/s^2

t = 3 sec

To find :-

distance = ?

solution :-

according to given  condition

accl^n = a = dv/dt

  a = d(kt)/dt

  a = k

as  , s = ut + 1/2 at^2

    s = 1/2 * k * t^2

   s = 9m

thank you