Question

The velocity-time relation of an electron starting from rest is given by u=kt,where k=2m/s2. The distance traserved in 3 sec.

Answer 1

v=kt ,k=2m/s^2 then
v=2t = 2×3=6m/s^2
v=u+at ,a=2m/s^2 for 3 sec
v^2 =u^2 +2as from here s =9m

Answer 2

Answer:

hope it helps u sir ❤❤❤❤❤❤