Question

the velocity time relation of an electron starting from the rest is given by u=kt, where k=2m/s2 and distance transversed in 3sec​

Answer 1

Answer:

Hello

Explanation:

v=kt ,k=2m/s^2 then

v=2t = 2×3=6m/s^2

v=u+at ,a=2m/s^2 for 3 sec

v^2 =u^2 +2as from here s =9m

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