Question

the velocity time( v-t) graph ABC of a moving particles shown in figure. the acceleration of the particles is
a) 5m/s2 b) 10m/s2 c) 20m/s2 d) 2.5m/s2​

Answer 1

Answer:

I think it's helped for you ☺

Explanation:

average velocity is 25m/s so distance will be 25×20=500m

now finding area of the graph between velocity and time graph we get

area of two triangles + area of rectangle.

2.

2

1

t.5.t+(25−2t).5t=500=>t

2

−25t+100

=>t=5

so option B is answer.