Question

the velocity v and displacement r of a body related as vsquare =kr, where k is constant. Find acceleration​

Answer 1

Dear Student,

◆ Answer -

a = k/2

● Explaination -

Given that,

v² = kr

v = √(kr)

Differentiating w.r.t. t,

dv/dt = d(√kr)/dt

a = √k × 1/√2r × dr/dt

a = √(k/2r) × v

a = √(k/2r) × √(kr)

a = k/2

Therefore, acceleration of the body is k/2.

Hope that was useful. Thanks for asking..