the velocity v and displacement r of a body related as vsquare =kr, where k is constant. Find acceleration
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Dear Student,
◆ Answer -
a = k/2
● Explaination -
Given that,
v² = kr
v = √(kr)
Differentiating w.r.t. t,
dv/dt = d(√kr)/dt
a = √k × 1/√2r × dr/dt
a = √(k/2r) × v
a = √(k/2r) × √(kr)
a = k/2
Therefore, acceleration of the body is k/2.
Hope that was useful. Thanks for asking..
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