Question

The velocity v of a moving particle varies with displacement as x = √(v+1) the acceleration of the particle at x = 5 unit will be
1) √6 unit
2) 24 unit
3) 240 unit
4) 25 unit​

Answer 1

Answer:

Question:-

• The velocity v of a moving particle varies with displacement as x = √(v+1) the acceleration of the particle at x = 5 unit will be:

Solution:-

$x = \sqrt{v + 1} = x {}^{2} = v + 1 \\ = v = (x {}^{2} - 1). \\ \\ a = \frac{dv}{dt} = \frac{d}{dt} (x {}^{2} - 1 ). \\ = 2x \frac{dx}{dt} = 2xv = 2x(x {}^{2} - 1 ). \\ \\ at \: x = 5ma = 2 \times 5(25 - 1) = 240m/s {}^{2} .$