Question

the velocity V of a particle at time T is given by the equal to at square + b upon c+ t square where a b c are constants. The dimensions of a * c is given by M^XL^YT^Z. the value of x + Y + Z is

Answer 1

Answer:

I don't know because sorry

Explanation:

I am in 8 class so I don't know

Answer 2

Given :   the velocity V of a particle at time T is given by the equal to

(at²  + b)/ (c + t²) where a b c are constants.

The dimensions of a * c is given by M^XL^YT^Z.

To Find  : the value of X + Y + Z is

Solution:

Velocity  V  = (at²  + b)/ (c + t²)

c + t²   hence dimension of  c  is  same as of t²

=> Dimensions of  c =  T²

Velocity  V  = m/s²     L / T²

Hence at²  + b    has dimension L  

at²  and b will have same dimension

dimension of b = L

=> Dimension of  a =  Dimension of b /  dimension of t²

=>  Dimension of  a  =  L/T²

dimensions of a * c   = (L/T² ) T²   = L

 dimensions of a * c   = M⁰L¹T⁰

X = 0  , Y = 1  , Z = 0

X + Y +  Z = 0 + 1 + 0 =  1

value of X + Y + Z = 1

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