Question

The velocity v of a particle varies with displacement as x=√(v-1), the acceleration of the particle at x=5 will be?

Answer 1

Answer:

find distance, velocity, acceleration of any equation by this method.

Answer 2

Answer:

The acceleration of the particles st x=5 will be 260 units

Explanation:

The acceleration of the particles is

a= dv/dt

= dv/dr× dr/dt

a = v×(dv/dx)

The velocity v of a particles

x= √(v-1)

Squaring in both sides

x²= v-1

v= x² + 1-------(1)

Differntiate the above one

dv/dx = 2x -------(2)

Subtitute (1)&(2) in the acceleration equation

a= v×(dv/dx)

a = (x²+1)2x

Subtitute x=5 in above

a = (5²+1)2×5

a= (25+1)10

a= 26×10

a= 260 units