The velocity v of a particle varies with displacement as x=√(v-1), the acceleration of the particle at x=5 will be?
Answers
Answered by
6
Answer:
find distance, velocity, acceleration of any equation by this method.
Attachments:
Answered by
0
Answer:
The acceleration of the particles st x=5 will be 260 units
Explanation:
The acceleration of the particles is
a= dv/dt
= dv/dr× dr/dt
a = v×(dv/dx)
The velocity v of a particles
x= √(v-1)
Squaring in both sides
x²= v-1
v= x² + 1-------(1)
Differntiate the above one
dv/dx = 2x -------(2)
Subtitute (1)&(2) in the acceleration equation
a= v×(dv/dx)
a = (x²+1)2x
Subtitute x=5 in above
a = (5²+1)2×5
a= (25+1)10
a= 26×10
a= 260 units
Similar questions