the velocity v of an object depends on time t as v = 3t + 2. From the start, the velocity of the particle is. a) first increasing and then decreasing. b) first decreasing and then increasing. c) continuously increasing. d) continuously decreasing
Answers
Answered by
1
Answer:
6.5m
Explanation:
The relation is
dt
dx
=v where x is displacement and v is velocity which is given as v=3−t
so we have dx=vdt
after 3sec the direction of motion will get reversed.
so
on integrating both sides we get ∫
X=0
X
dx=∫
t=0
t=3
(3−t)dt=9−
2
9
=4.5meter
now integrating both sides for t=3 to t=5
we have the displacement as
∫
X=4.5
X
dx=∫
t=3
t=5
(3−t)dt=−2meter
so the net distance will be X=(2)+4.5=6.5meter
Answered by
1
Answer:
velocity v of an object depends on time t as v = 3t + 2. From the start, the velocity of the particle is. a) first increasing and then decreasing. b) first decreasing and then increasing. c) continuously increasing. d) continuously decreasing
Explanation:
first increasing and then decreasing
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