The velocity v of the body moving along a straight line varies with t as v=2t2e-1 where v is in m/s and tis in second. the acceleration of body is zero at t=
Sharu26:
V=2t ....it's square to t 2 and er
And rise to e -1
t rise to 2
Ans 0 and 2
How 0 comes the ans ?
Ok thx
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2
V=2t^2e^(-1)right
First tell
If yes than after differentiate the equation we get a=4te@^-1
Than t =0
First tell
If yes than after differentiate the equation we get a=4te@^-1
Than t =0
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