Question

the velocity v verse t graph of the body ina straight line is as shows in figure:​

Answer 1

Answer:

$d = \frac{v}{t} \\ at \: 4sec \: the \: velocity \: is \: 0 \: so - \\ d = \frac{0}{4} \\ d = 0$

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Answer 2

First find the area of the first triangle. Consider the area A1 :-

1/2(base)(height)

⟶ Base is from 0 to 3 that is 3 [3 - 0 = 3] (x axis)

⟶ Height is from 0 to 2 that is 2 [2 - 0 = 2] (y axis)

so, 1/2(3)(2)

= 3

Then find the area of the second triangle. Consider the area A2:-

1/2(base)(height)

⟶ base is from 3 to 4 that is 1 [4 - 3 = 1](x axis)

⟶ height is from 0 to -2 that is [ -2 - 0 = -2] (y axis) but we will not consider minus( - ) here as we are just counting the units that are in between so there is no concept of negative. So here value of height is 2

1/2(1)(2)

=1

$\huge{\red{\sf{\boxed{\boxed{Displacement\:=A1\:-A2}}}}}$

⟶ Displacement = 3m - 1m

⟶ Displacement = 2m