Physics, asked by rawhanazeer1234, 1 year ago

The velocity varies with time as v= ai + btj, where i and j are unit vectors and a and b are positive constants .Then magnitude of instantaneous velocity and acceleration would be?

Answers

Answered by adrija70
25

Please refer to the attachment.

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Answered by AneesKakar
3

Answer:

Instantaneous velocity is ✓[a^2 + (bt)^2] and acceleration is b.

Explanation:

Since, the magnitude of instantaneous velocity is ✓(a^2 + (bt)^2) again on solving this equation we will get the value of instantaneous velocity as ✓[a^2 + (bt)^2].

Again, to find the acceleration of the particle we have to differentiate the given velocity of the particle will be d/dt(ai + btj) which on differentiating we will get the acceleration as 0 + bj.

Hence, the magnitude of acceleration will be b.

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