The velocity varies with time as v= ai + btj, where i and j are unit vectors and a and b are positive constants .Then magnitude of instantaneous velocity and acceleration would be?
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Answer:
Instantaneous velocity is ✓[a^2 + (bt)^2] and acceleration is b.
Explanation:
Since, the magnitude of instantaneous velocity is ✓(a^2 + (bt)^2) again on solving this equation we will get the value of instantaneous velocity as ✓[a^2 + (bt)^2].
Again, to find the acceleration of the particle we have to differentiate the given velocity of the particle will be d/dt(ai + btj) which on differentiating we will get the acceleration as 0 + bj.
Hence, the magnitude of acceleration will be b.
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