Question

The velocity versus time curve of a moving point
shown in the figure. The maximum acceleration is

(a) 1 m/s2
(b) 4 m/s2
(c) 2 m/s2
(d) 1.5 m/s2​

Answer 1

Answer:

The maximum acceleration is 4m/s²i.e.option(b).

Explanation:

The acceleration(a) is given as,

$a=\frac{v}{t}$             (1)

v=velocity of the particle

t=time in which the change has occurred

For the part A to B

The acceleration is given as,

$a_1=\frac{20}{20}=1m/s^2$

For the part B to C

The acceleration is given as,

$a_2=0m/s^2$       (∴ as the velocity is not changing from B to C)

For the part C to D

The acceleration is given as,

$a_3=\frac{60-20}{40-30}=\frac{40}{10}=4m/s^2$

For the part D to E

The acceleration is given as,

$a_4=0 m/s^2$          (∴ as the velocity is not changing from B to C)

For the part E to F

The acceleration is given as,

$a_5=\frac{0-60}{90-60}=\frac{-60}{30}=-2m/s^2$  (∴ as the velocity is decreasing from E to F)

Hence, the maximum acceleration is 4m/s²i.e.option(b).