Question

The vernier scale of a travelling microscope has 50 divisions which coincide with 49 main scale divisions. If each main scale division is 0.5 mm, calculate the minimum inaccuracy in the measurement of distance.

Answer 1

the least count = 1/50.

so precision in measurements  =  1/50 * 0.5 mm = 0.01 mm

Answer 2

Answer:

The minimum inaccuracy is 0.1 mm.

Explanation:

Here 50 Vernier scale Divisions = 49 Main scale divisions

1 Vernier scale division  $=\frac{49}{50}$ ain scale Divisions

Now as we know that, Minimum inaccuracy = Vernier constant

Minimum inaccuracy = 1 Main scale division – 1 Vernier scale division

= 1 Main scale division –  $\frac{49}{50}$ Main scale Divisions  

Value of each main scale division is 0.5 mm

So Minimum inaccuracy $=\frac{1}{50}$ Main scale Divisions  $=\frac{1}{50} \times 0.5=\bold{0.01 \mathrm{mm}}$