Question

The vernier scale of an instrument has 50 divisions which coincide with 49 main scale divisions.
If each main scale division is 0.5 mm, then using this instruments what would be the minimum
in accuracy in the measurement of distance?​

Answer 1

Answer:

• 0.01 mm

Explanation:

• vernier scale division = 50
• 1 main scale division (M.S.D.) = 0.5mm

$\tiny{\boxed{\sf{(n+1)\: divisions\: of\: vernier\: scale= n\: divisions\:of \:main\:scale}}}$

50VSD = 49MSD

→ 1 VSD = $\frac{49}{50}$ (1 MSD)

→ $\frac{49}{50}$(0.5) = 49×10$^{-2}$

→ 0.49 mm

→ Least count = 1Msd-1Vsd

→ Least count = 0.5 - 0.49

→ Least count = 0.01 mm

⛬ The minimum inaccuracy in the measurement of distance is 0.1 mm.