Question

The vernier scale of an instrument has 50 divisions which coincide with 49 main scale divisions. If each main scale division is 0.5 mm, then using this instrument what would be the minimum inaccuracy in the measurement of distance?

Answer 1

Hii dear,

# Answer- 0.01 mm

# Explaination-
Consider,
MSD = main scale division
VSD = vernier scale division

- Given is-
MSD = 0.5 mm
50 VSD coincide with 49 VSD.
50 VSD = 49 MSD
VSD = 49/50 MSD

Least count of instrument
LC = 1 MSD - 1 VSD
LC = 1 MSD - 49/50 MSD
LC = 1/50 MSD
LC = 1/50 × 0.5
LC = 0.01 mm

Minimum inaccuracy is nothing but least count i.e. 0.01 mm.

Hope that was useful...

Answer 2

Answer:

The correct answer is 0.01mm

Explanation:

here minimum accuracy means least count

least count = value of one main scale/number of division of vernier scale

LC=0.5/50mm

=0.01mm