Question

the version angle of an isosceles triangle measure (2p+18) and one of the base angles measure 2p find the value of all the angles of the triangle​

Answer 1

Answer:

Since it is an isosceles triangle, base angles will be equal.

therefore, sum total of all angles of triangle = (2p + 18) + 2p + 2p

180 = (2p + 18) + 2p + 2p

180 = 6p + 18

6p = 180 - 18

6p = 162

p = 27

hence base angles = 2p = 2×27 = 54 each

vertex angle = 2p + 18 = 54 + 18 = 72