the vertex angle of an isosceles triangle is 120° . find the remaining two angles
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In triangle ABC
Angles A+B+C=180°(ASP)
Angle A=B( Isosceles Trinagle)
Therefore 2A+ 120°=180°
A=30°
B=30°
Angles A+B+C=180°(ASP)
Angle A=B( Isosceles Trinagle)
Therefore 2A+ 120°=180°
A=30°
B=30°
Answered by
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let ABC is the isosceles triangle
and A=120°,B= x , C= x
and we know that the sum of all angles of a triangle =180°
Angle ( A+B + C ) = 180
120 +x+x = 180
2x = 180 - 120
2x= 60
x = 60÷2
x= 30°
so B and C = 30°
and A=120°,B= x , C= x
and we know that the sum of all angles of a triangle =180°
Angle ( A+B + C ) = 180
120 +x+x = 180
2x = 180 - 120
2x= 60
x = 60÷2
x= 30°
so B and C = 30°
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