Question

the vertex angle of an isosceles triangle is 15 degree more than each of its base angles find the angles.​

Answer 1

Answer:

here is the answer.....

Answer 2

$Let \: each \: of \: the \: base \: angle \: of$

$isosceles \: triangle = x\degree$

$Vertex \: angle = ( x + 15 ) \degree$

/* By Angle Sum Property */

$Sum \: of \: the \: angles = 180\degree$

$\implies x + x + ( x + 15 ) = 180\degree$

$\implies 3x + 15 = 180$

$\implies 3x = 180 - 15$

$\implies 3x = 165$

$\implies x = \frac{165}{3}$

$\implies x = 55\degree$

Therefore,.

$\red{ Each \: base \: angle } \green { = 55\degree}$

$\red{ Vertex \: angle } = x + 15$

$= 55 + 15$

$= 70 \degree$

$\red{ Required \: three \: angles }$

$\green { = 55 \degree, 55 \degree\:and \: 70 \degree }$

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