Math, asked by sanvibolt, 10 months ago

The vertex angle of two isosceles triangles are equal and their areas are in ratio 64:225. Find the ratio of their corresponding altitudes.​

Answers

Answered by amitnrw
0

Given :  The vertex angle of two isosceles triangles are equal and their areas are in ratio 64:225

To find : ratio of their corresponding altitudes.​

Solution:

Vertex angle of  two isosceles triangles are equal

=> Both isosceles triangles are similar

( let say two triangle ABC  & PQR

∠A = ∠P

∠B = ∠C = (180 - A)/2

∠Q = ∠R = (180 - P)/2

∠A = ∠P => ∠B = ∠C = ∠Q = ∠R =

Hence ΔABC ≈ Δ PQR

For similar triangles

Ratio of area of triangle =  Ratio of corresponding sides²

=> 64 : 225=  Ratio of corresponding sides²

=> 8 : 15=  Ratio of corresponding sides

For similar triangles

Ratio of corresponding altitudes = Ratio of corresponding sides

=> Ratio of corresponding altitudes = 8 : 15

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